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2x^2+4x+100=676
We move all terms to the left:
2x^2+4x+100-(676)=0
We add all the numbers together, and all the variables
2x^2+4x-576=0
a = 2; b = 4; c = -576;
Δ = b2-4ac
Δ = 42-4·2·(-576)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-68}{2*2}=\frac{-72}{4} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+68}{2*2}=\frac{64}{4} =16 $
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